Tardigrade
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Physics
For a gas CP-CV=R in a state P and CP-CV=1.10 R in a state Q, TP and TQ are the temperatures in two different states P and Q respectively. Then
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Q. For a gas $C_{P}-C_{V}=R$ in a state $P$ and $C_{P}-C_{V}=1.10\, R$ in a state $Q, T_{P}$ and $T_{Q}$ are the temperatures in two different states $P$ and $Q$ respectively. Then
JEE Main
JEE Main 2021
Kinetic Theory
A
$T_{P}=T_{Q}$
B
$T_{P} < T_{Q}$
C
$T_{P}=0.9\, T_{Q}$
D
$T_{P} >T_{Q}$
Solution:
$C_{P}-C_{V}=R$ for ideal gas and gas behaves as ideal gas at high temperature
so $T_{P} > T_{Q}$