A body of mass 0.05 kg is observed to fall with an acceleration of 9.5 ms-2. The opposing force of air on the body is(g = 9.8 ms-2).

Question

A body of mass 0.05 kg is observed to fall with an acceleration of 9.5 ms-2. The opposing force of air on the body is(g = 9.8 ms-2). (A) 0.15 N (B) 0.030 N (C) Zero (D) 0.015 N

Tardigrade Admin · Accepted Answer

From, Newton's laws of motion, <img class="img-fluid question-image" alt="image" src="https://cdn.tardigrade.in/img/question/physics/d1438697aad73e1361c5f4c248f22cc6-.png" /> m g-F text air =m a or F text air =m(g-a) =0.05(9.8-9.5) =0.015 N

Q. A body of mass $0.05 k g$ is observed to fall with an acceleration of $9.5 m s^{- 2}$ . The opposing force of air on the body is______ $(g = 9.8 m s^{- 2}) .$

0.15 N

0.030 N

Zero

0.015 N

From, Newton's laws of motion,

$m g - F_{air} = ma$
or $F_{air} = m (g - a)$
$= 0.05 (9.8 - 9.5)$
$= 0.015 N$

Q. A body of mass 0.05kg is observed to fall with an acceleration of 9.5ms−2. The opposing force of air on the body is______(g=9.8ms−2).