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  4. A body of mass 0.05 kg is observed to fall with an acceleration of 9.5 ms-2. The opposing force of air on the body is(g = 9.8 ms-2).

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Q. A body of mass $0.05\, kg$ is observed to fall with an acceleration of $9.5\, ms^{-2}$. The opposing force of air on the body is______$(g = 9.8\, ms^{-2}).$

KCETKCET 2009Laws of Motion

Solution:

From, Newton's laws of motion,
image
$m g-F_{\text {air }} =m a $
or $\,\,\,\, F_{\text {air }} =m(g-a) $
$=0.05(9.8-9.5) $
$=0.015\, N $