A body is moving with uniform velocity of 8 ms-1. When the body just crossed another body, the second one starts and moves with uniform acceleration of 4 ms-2. The time after which two bodies meet will be:

Question

A body is moving with uniform velocity of 8 ms-1. When the body just crossed another body, the second one starts and moves with uniform acceleration of 4 ms-2. The time after which two bodies meet will be: (A) 2 s (B) 4 s (C) 6 s (D) 8 s

Tardigrade Admin · Accepted Answer

Let they meet after time t. Then distance traveled by both in time t should be same. s = 8t = (1/2) 4t2 ⇒ t = 4 s

Q. A body is moving with uniform velocity of $8 m s^{- 1}$ . When the body just crossed another body, the second one starts and moves with uniform acceleration of $4 m s^{- 2}$ . The time after which two bodies meet will be:

2 s

4 s

6 s

8 s

Let they meet after time $t$ . Then distance traveled by both in time $t$ should be same.

$s = 8 t = \frac{1}{2} 4 t^{2}$

$\Rightarrow t = 4 s$

Q. A body is moving with uniform velocity of 8ms−1. When the body just crossed another body, the second one starts and moves with uniform acceleration of 4ms−2. The time after which two bodies meet will be:

2 s

4 s

6 s

8 s

Let they meet after time t. Then distance traveled by both in time t should be same. s=8t=21​4t2 ⇒t=4s

Q. A body is moving with uniform velocity of $8 m s^{- 1}$ . When the body just crossed another body, the second one starts and moves with uniform acceleration of $4 m s^{- 2}$ . The time after which two bodies meet will be:

Let they meet after time $t$ . Then distance traveled by both in time $t$ should be same.

$s = 8 t = \frac{1}{2} 4 t^{2}$

$\Rightarrow t = 4 s$