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Q. A body is moving with uniform velocity of $8 \,ms^{-1}$. When the body just crossed another body, the second one starts and moves with uniform acceleration of $4 \,ms^{-2}$. The time after which two bodies meet will be:

Motion in a Straight Line

Solution:

Let they meet after time $t$. Then distance traveled by both in time $t$ should be same.
$ s = 8t = \frac{1}{2} 4t^2$
$\Rightarrow t = 4\,s$