A body falls freely for 10 sec. Its average velocity during this journey (take g = 10 ms-2)

Question

A body falls freely for 10 sec. Its average velocity during this journey (take g = 10 ms-2) (A) 100 ms-1 (B) 10 ms-1 (C) 50 ms-1 (D) 5 ms-1

Tardigrade Admin · Accepted Answer

Key Idea Average velocity =( text Total Displacement / text Time interval ) In 10 s, the distance covered by the body Here, s=(1/2) g t2 t=10 s g =10 ms -2 ∴ s =(1/2)(10) ×(10)2=500 m v av =(500/10)=50 ms -1

Q. A body falls freely for $10 sec$ . Its average velocity during this journey (take $g = 10 m s^{- 2}$ )

$100 m s^{- 1}$

$10 m s^{- 1}$

$50 m s^{- 1}$

$5 m s^{- 1}$

Key Idea Average velocity $= \frac{Total Displacement}{Time interval}$
In $10 s$ , the distance covered by the body
Here,
$s = \frac{1}{2} g t^{2}$
$t = 10 s$
$g = 10 m s^{- 2}$
$∴ s = \frac{1}{2} (10) \times (10)^{2} = 500 m$
$v_{a v} = \frac{500}{10} = 50 m s^{- 1}$

Q. A body falls freely for 10sec. Its average velocity during this journey (take g=10ms−2)

100ms−1

10ms−1

50ms−1

5ms−1