A body falls freely for 10 s . Its average velocity during this journey is ( textTake g = 10 m s- 2)

Question

A body falls freely for 10 s . Its average velocity during this journey is ( textTake g = 10 m s- 2) (A) 100 m s- 1 (B) 10 m s- 1  (C) 50 m s- 1  (D) 5 m s- 1

Tardigrade Admin · Accepted Answer

Average velocity =(T o t a l D i s p l a c e m e n t/T i m e i n t e r v a l) In 10 s, the distance covered by the body s=(1/2)gt2 ∴ s=(1/2)(10)× (10)2=500 m νa v=(500/10)=50 m s- 1

Q. A body falls freely for $10 s$ . Its average velocity during this journey is $(Take g = 10 m s^{- 2})$

$100 m s^{- 1}$

$10 m s^{- 1}$

$50 m s^{- 1}$

$5 m s^{- 1}$

Average velocity
$= \frac{T o t a l D i s pl a ce m e n t}{T im e in t er v a l}$
In 10 s, the distance covered by the body
$s = \frac{1}{2} g t^{2}$
$∴ s = \frac{1}{2} (10) \times (10)^{2} = 500 m$
$ν_{a v} = \frac{500}{10} = 50 m s^{- 1}$

Q. A body falls freely for 10s . Its average velocity during this journey is (Take g=10ms−2)

100ms−1

10ms−1

50ms−1

5ms−1