A block of mass m is placed in equilibrium on a moving plank. The maximum horizontal acceleration of the plank for μ=0.2 is:

Question

A block of mass m is placed in equilibrium on a moving plank. The maximum horizontal acceleration of the plank for μ=0.2 is: (A) 2 m/s2 (B) 3 m/s2 (C) dependent on the mass m (D) none of these

Tardigrade Admin · Accepted Answer

<img class="img-fluid question-image" alt="image" src="https://cdn.tardigrade.in/img/question/physics/edfdaad48891dd82446879ebc348a9a4-.png" /> If block does not slide w.r.t platform F=ma ...(i) but f le μ N ... (ii) From (i) and (ii), ma le μ mg a le μ g Hence maximum acceleration of the plank is 0.2 × 10=2 m/s2

Q. A block of mass m is placed in equilibrium on a moving plank. The maximum horizontal acceleration of the plank for $μ = 0.2$ is:

$2 m / s^{2}$

$3 m / s^{2}$

dependent on the mass $m$

none of these

If block does not slide w.r.t platform

$F = ma ... (i)$

but $f \leq μ N ... (ii)$

From (i) and (ii), $ma \leq μ m g$

$a \leq μ g$

Hence maximum acceleration of the plank is

$0.2 \times 10 = 2 m / s^{2}$

Q. A block of mass m is placed in equilibrium on a moving plank. The maximum horizontal acceleration of the plank for μ=0.2 is:

2m/s2

3m/s2

dependent on the mass m