A block of mass 2.5 kg is heated to temperature of 500° C and placed on a large ice block. What is the maximum amount of ice (in g ) that can melt (approximate to nearest integer). Specific heat for the body =0.1 Cal/gm° C.

Question

A block of mass 2.5 kg is heated to temperature of 500° C and placed on a large ice block. What is the maximum amount of ice (in g ) that can melt (approximate to nearest integer). Specific heat for the body =0.1 Cal/gm° C. (A)  (B)  (C)  (D)

Tardigrade Admin · Accepted Answer

Let the amount of ice that melts is m . Then mL=msΔ θ m× 80=2500× 0.1× 500⇒ m=1562.5 g⇒ m≈1.5 kg

Q. A block of mass $2.5 k g$ is heated to temperature of $50 0^{\circ} C$ and placed on a large ice block. What is the maximum amount of ice (in $g$ ) that can melt (approximate to nearest integer). Specific heat for the body $= 0.1 C a l / g m^{\circ} C .$

Let the amount of ice that melts is $m$ .
Then
$m L = m s Δ θ$
$m \times 80 = 2500 \times 0.1 \times 500 \Rightarrow m = 1562.5 g \Rightarrow m \approx 1.5 k g$

Q. A block of mass 2.5kg is heated to temperature of 500∘C and placed on a large ice block. What is the maximum amount of ice (in g ) that can melt (approximate to nearest integer). Specific heat for the body =0.1Cal/gm∘C.

Let the amount of ice that melts is m . Then mL=msΔθ m×80=2500×0.1×500⇒m=1562.5g⇒m≈1.5kg

Q. A block of mass $2.5 k g$ is heated to temperature of $50 0^{\circ} C$ and placed on a large ice block. What is the maximum amount of ice (in $g$ ) that can melt (approximate to nearest integer). Specific heat for the body $= 0.1 C a l / g m^{\circ} C .$

Let the amount of ice that melts is $m$ .
Then
$m L = m s Δ θ$
$m \times 80 = 2500 \times 0.1 \times 500 \Rightarrow m = 1562.5 g \Rightarrow m \approx 1.5 k g$