A block of mass 0.1 kg is held against a wall by applying a horizontal force of 5 N on it. If μ, between the wall· and the block is 0.5, the magnitude of the frictional force acting on the block is

Question

A block of mass 0.1 kg is held against a wall by applying a horizontal force of 5 N on it. If μ, between the wall· and the block is 0.5, the magnitude of the frictional force acting on the block is (A) 0.98 N (B) 0.49 N (C) 4.9 N (D) 2.5 N

Tardigrade Admin · Accepted Answer

Refer figure. Limiting value of frictional force, f max =μ N =.5 × 5=2.5 N Now, value of mg =0.1 × 9.8=0.98 N f max > mg then frictional force acting on block is f = mg =0.98 N

Q. A block of mass 0.1 kg is held against a wall by applying a horizontal force of 5 N on it. If $μ,$ between the wall· and the block is 0.5, the magnitude of the frictional force acting on the block is

0.98 N

0.49 N

4.9 N

2.5 N

Refer figure.
Limiting value of frictional force,
$f_{m a x} = μ N = .5 \times 5 = 2.5 N$
Now, value of $m g = 0.1 \times 9.8 = 0.98 N$
$f_{m a x} > m g$
then frictional force acting on block is
$f = m g = 0.98 N$

Q. A block of mass 0.1 kg is held against a wall by applying a horizontal force of 5 N on it. If μ, between the wall· and the block is 0.5, the magnitude of the frictional force acting on the block is