Question

A bar magnet of magnetic moment $5.0A{m}^2$ has poles $20cm$ apart. The pole strength (in $Am$ ) is ___

Answer 1

Answer: 25

The magnetic moment $M=5.0A{m}^2$
The separation between its poles
$2l=20cm=20\times 10^{-2}m$
Pole strength, $m=\frac{M}{2l}=\frac{5.0A{m}^2}{20\times 10^{-2}m}=25Am$