Question Error Report

Thank you for reporting, we will resolve it shortly

Back to Question

Q. A bar magnet of magnetic moment $5.0\, Am ^{2}$ has poles $20 \,cm$ apart. The pole strength (in $Am$ ) is ___

Magnetism and Matter

Solution:

The magnetic moment $M=5.0\, Am ^{2}$
The separation between its poles
$2 l=20\, cm =20 \times 10^{-2}\, m$
Pole strength, $m=\frac{M}{2 l}=\frac{5.0 Am ^{2}}{20 \times 10^{-2} m }=25 \,Am$