A bar magnet is oscillating in a magnetic field and its frequency is 10 Hz.If another identical piece of brass be placed over that magnet, the frequency of that combination in that field is

Question

A bar magnet is oscillating in a magnetic field and its frequency is 10 Hz.If another identical piece of brass be placed over that magnet, the frequency of that combination in that field is (A) 20 Hz (B) 10 Hz (C) (10/√2) Hz (D) 10 √2 Hz

Tardigrade Admin · Accepted Answer

n=(1/2 π) √(M B/I) (n2/n1)=√(I1/I2) n2=10 √(I/2 I) =(10/√2) H z

Q. A bar magnet is oscillating in a magnetic field and its frequency is $10 Hz$ .If another identical piece of brass be placed over that magnet, the frequency of that combination in that field is

$20 Hz$

$10 Hz$

$\frac{10}{2} Hz$

$102 Hz$

$n = \frac{1}{2 π} \frac{MB}{I}$
$\frac{n _{2}}{n _{1}} = \frac{I _{1}}{I _{2}}$
$n_{2} = 10 \frac{I}{2 I}$
$= \frac{10}{2} Hz$

Q. A bar magnet is oscillating in a magnetic field and its frequency is 10Hz.If another identical piece of brass be placed over that magnet, the frequency of that combination in that field is

20Hz

10Hz

2​10​Hz

102​Hz