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Q. A bar magnet is oscillating in a magnetic field and its frequency is $10\, Hz$.If another identical piece of brass be placed over that magnet, the frequency of that combination in that field is

Solution:

$n=\frac{1}{2 \pi} \sqrt{\frac{M B}{I}} $
$\frac{n_{2}}{n_{1}}=\sqrt{\frac{I_{1}}{I_{2}}}$
$n_{2}=10 \sqrt{\frac{I}{2 I}}$
$=\frac{10}{\sqrt{2}} \,H z$