A bar magnet has a magnetic moment of 2.5 JT-1 and is placed in a magnetic Held of 0.2T. Work done in turning the magnet from parallel to antiparallel position relative to field direction is

Question

A bar magnet has a magnetic moment of 2.5 JT-1 and is placed in a magnetic Held of 0.2T. Work done in turning the magnet from parallel to antiparallel position relative to field direction is (A) 0.5 J (B) 1 J (C) 2 J (D) 0 J

Tardigrade Admin · Accepted Answer

Work done, W = - MB(cos θ2 - cos θ1) = - MB(cos 180° - cos 0°) = - MB(-1 - 1) = - MB( - 2) = 2 MB = 2 × 2.5 × 0.2 = 1 J

Q. A bar magnet has a magnetic moment of $2.5 J T^{- 1}$ and is placed in a magnetic Held of 0.2T. Work done in turning the magnet from parallel to antiparallel position relative to field direction is

0.5 J

1 J

2 J

0 J

Work done, W = - MB(cos $θ_{2}$ - cos $θ_{1}$ )
= - MB(cos 180 $\circ$ - cos 0 $\circ$ ) = - MB(-1 - 1)
= - MB( - 2) = 2 MB = 2 $\times$ 2.5 $\times$ 0.2 = 1 J

Q. A bar magnet has a magnetic moment of 2.5JT−1 and is placed in a magnetic Held of 0.2T. Work done in turning the magnet from parallel to antiparallel position relative to field direction is

0.5 J

1 J

2 J

0 J

Work done, W = - MB(cos θ2​ - cos θ1​) = - MB(cos 180∘ - cos 0∘) = - MB(-1 - 1) = - MB( - 2) = 2 MB = 2 × 2.5 × 0.2 = 1 J

Q. A bar magnet has a magnetic moment of $2.5 J T^{- 1}$ and is placed in a magnetic Held of 0.2T. Work done in turning the magnet from parallel to antiparallel position relative to field direction is

Work done, W = - MB(cos $θ_{2}$ - cos $θ_{1}$ )
= - MB(cos 180 $\circ$ - cos 0 $\circ$ ) = - MB(-1 - 1)
= - MB( - 2) = 2 MB = 2 $\times$ 2.5 $\times$ 0.2 = 1 J