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  4. A bar magnet has a magnetic moment of 2.5 JT-1 and is placed in a magnetic Held of 0.2T. Work done in turning the magnet from parallel to antiparallel position relative to field direction is

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Q. A bar magnet has a magnetic moment of $2.5\,JT^{-1}$ and is placed in a magnetic Held of 0.2T. Work done in turning the magnet from parallel to antiparallel position relative to field direction is

Solution:

Work done, W = - MB(cos $\theta_2$ - cos $\theta_1$)
= - MB(cos 180$\circ$ - cos 0$\circ$) = - MB(-1 - 1)
= - MB( - 2) = 2 MB = 2 $\times$ 2.5 $\times$ 0.2 = 1 J