A ball of mass 160 g is thrown up at an angle of 60° to the horizontal at a speed of 10 ms-1. The angular momentum of the ball at the highest point of the trajectory with respect to the point from which the ball is thrown is nearly (g = 10 ms-2)

Question

A ball of mass 160 g is thrown up at an angle of 60° to the horizontal at a speed of 10 ms-1. The angular momentum of the ball at the highest point of the trajectory with respect to the point from which the ball is thrown is nearly (g = 10 ms-2) (A) 1.73 kg m2/s (B) 3.0 kg m2/s (C) 3.46 kg m2/ s (D) 6.0 kg m2/ s

Tardigrade Admin · Accepted Answer

<img class="img-fluid question-image" alt="image" src="https://cdn.tardigrade.in/img/question/physics/b2d9b314df33a72501b00bf2c647e3b1-.png" /> overline L = overline r × overline10 =(160/1000) × 10 × (1/2) × (10 × 10/2 × 10)((√3/2))2 =10 × (1/2) × (1/2) × (3/4)=3

Q. A ball of mass $160 g$ is thrown up at an angle of $6 0^{\circ}$ to the horizontal at a speed of $10 m s^{- 1}$ . The angular momentum of the ball at the highest point of the trajectory with respect to the point from which the ball is thrown is nearly ( $g = 10 m s^{- 2}$ )

1.73 kg m²/s

3.0 kg m²/s

3.46 kg m²/ s

6.0 kg m²/ s

$\overline{L} = \overline{r} \times \overline{10}$
$= \frac{160}{1000} \times 10 \times \frac{1}{2} \times \frac{10 \times 10}{2 \times 10} (\frac{3}{2})^{2}$
$= 10 \times \frac{1}{2} \times \frac{1}{2} \times \frac{3}{4} = 3$

Q. A ball of mass 160g is thrown up at an angle of 60∘ to the horizontal at a speed of 10ms−1. The angular momentum of the ball at the highest point of the trajectory with respect to the point from which the ball is thrown is nearly (g=10ms−2)

1.73 kg m2/s

3.0 kg m2/s

3.46 kg m2/ s

6.0 kg m2/ s