Question

A ball of mass $160\, g$ is thrown up at an angle of $60^\circ$ to the horizontal at a speed of $10\, ms^{-1}$. The angular momentum of the ball at the highest point of the trajectory with respect to the point from which the ball is thrown is nearly ($g = 10\, ms^{-2}$)

• A. 1.73 kg m²/s
• B. 3.0 kg m²/s
• C. 3.46 kg m²/ s
• D. 6.0 kg m²/ s

Answer 1

Answer: (B)

$\overline{ L }=\overline{ r } \times \overline{10}$
$=\frac{160}{1000} \times 10 \times \frac{1}{2} \times \frac{10 \times 10}{2 \times 10}\left(\frac{\sqrt{3}}{2}\right)^{2} $
$=10 \times \frac{1}{2} \times \frac{1}{2} \times \frac{3}{4}=3$