A ball is thrown vertically upward. It has a speed of 10 m/ sec when it has reached one half of its maximum height. How high does the ball rise? Take g = 10 m/s2.

Question

A ball is thrown vertically upward. It has a speed of 10 m/ sec when it has reached one half of its maximum height. How high does the ball rise? Take g = 10 m/s2. (A) 10 m (B) 5 m (C) 15 m (D) 20 m

Tardigrade Admin · Accepted Answer

v2 =u2 - 2gh After reaching maximum height velocity becomes zero. 0 = (10)2 - 2 × 10 × (h/2) ∴ h = (200/20) = 10 m.

Q. A ball is thrown vertically upward. It has a speed of $10 m / sec$ when it has reached one half of its maximum height. How high does the ball rise?
Take $g = 10 m / s^{2} .$

10 m

5 m

15 m

20 m

$v^{2} = u^{2} - 2 g h$
After reaching maximum height velocity becomes zero.
$0 = (10)^{2} - 2 \times 10 \times \frac{h}{2}$
$∴ h = \frac{200}{20} = 10 m .$

Q. A ball is thrown vertically upward. It has a speed of 10m/sec when it has reached one half of its maximum height. How high does the ball rise? Take g=10m/s2.

10 m

5 m

15 m

20 m

v2=u2−2gh After reaching maximum height velocity becomes zero. 0=(10)2−2×10×2h​ ∴h=20200​=10m.

Q. A ball is thrown vertically upward. It has a speed of $10 m / sec$ when it has reached one half of its maximum height. How high does the ball rise?
Take $g = 10 m / s^{2} .$

$v^{2} = u^{2} - 2 g h$
After reaching maximum height velocity becomes zero.
$0 = (10)^{2} - 2 \times 10 \times \frac{h}{2}$
$∴ h = \frac{200}{20} = 10 m .$