Question

A ball is thrown vertically upward. It has a speed of $10 \,m/ \sec$ when it has reached one half of its maximum height. How high does the ball rise?
Take $g = 10\, m/s^2.$

• A. 10 m
• B. 5 m
• C. 15 m
• D. 20 m

Answer 1

Answer: (A)

$v^2 =u^2 - 2gh$
After reaching maximum height velocity becomes zero.
$0 = (10)^2 - 2 \times 10 \times \frac{h}{2} $
$ \therefore h = \frac{200}{20} = 10\, m.$