A ball is released from the top of a tower. The ratio of work done by force of gravity in first, second and third second of the motion of the ball is

Question

A ball is released from the top of a tower. The ratio of work done by force of gravity in first, second and third second of the motion of the ball is (A) 1:2:3 (B) 1:4:9 (C) 1:3:5 (D) 1:5:3

Tardigrade Admin · Accepted Answer

When the ball is released from the top of tower then ratio of distances covered by the ball in first. second and third second

h_{I} : h_{II} : h_{III} = 1 : 3 : 5

[because

h_{n} \propto (2 n - 1)

Ratio of work done

m g h_{I} : m g h_{II} : m g h_{III} = 1 : 3 : 5

Q. A ball is released from the top of a tower. The ratio of work done by force of gravity in first, second and third second of the motion of the ball is

$1 : 2 : 3$

$1 : 4 : 9$

$1 : 3 : 5$

$1 : 5 : 3$

When the ball is released from the top of tower then ratio of distances covered by the ball in first. second and third second
$h_{I} : h_{II} : h_{III} = 1 : 3 : 5$ [because $h_{n} \propto (2 n - 1)$
Ratio of work done $m g h_{I} : m g h_{II} : m g h_{III} = 1 : 3 : 5$

Q. A ball is released from the top of a tower. The ratio of work done by force of gravity in first, second and third second of the motion of the ball is

1:2:3

1:4:9

1:3:5

1:5:3

When the ball is released from the top of tower then ratio of distances covered by the ball in first. second and third second hI​:hII​:hIII​=1:3:5 [because hn​∝(2n−1) Ratio of work done mghI​:mghII​:mghIII​=1:3:5

$1 : 2 : 3$

$1 : 4 : 9$

$1 : 3 : 5$

$1 : 5 : 3$

When the ball is released from the top of tower then ratio of distances covered by the ball in first. second and third second
$h_{I} : h_{II} : h_{III} = 1 : 3 : 5$ [because $h_{n} \propto (2 n - 1)$
Ratio of work done $m g h_{I} : m g h_{II} : m g h_{III} = 1 : 3 : 5$