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Q.
A ball is released from the top of a tower. The ratio of work done by force of gravity in first, second and third second of the motion of the ball is
NTA AbhyasNTA Abhyas 2022
Solution:
When the ball is released from the top of tower then ratio of distances covered by the ball in first. second and third second
$h_{I}:h_{I I}:h_{I I I}=1:3:5$ [because $h_{n} \propto \left(2 n - 1\right)$
Ratio of work done $mgh_{I}:mgh_{I I}:mgh_{I I I}=1:3:5$