A ball is projected vertically upwards. Its speed at half of maximum height is 20 m / s. The maximum height attained by it is [Take .g=10 ms 2]

Question

A ball is projected vertically upwards. Its speed at half of maximum height is 20 m / s. The maximum height attained by it is [Take .g=10 ms 2] (A) 35 m (B) 15 m (C) 25 m (D) 40 m

Tardigrade Admin · Accepted Answer

<img class="img-fluid question-image" alt="image" src="https://cdn.tardigrade.in/img/question/physics/c095bdc03a83468aaffbe02236e21cde-.png" /> vB2-vA2=-2 g((H/2)) ⇒ 0-400=-2 × 10 × (H/2) ⇒ 40 m = H

Q. A ball is projected vertically upwards. Its speed at half of maximum height is $20 m / s$ . The maximum height attained by it is [Take $g = 10 m s^{2}]$

35 m

15 m

25 m

40 m

$v_{B}^{2} - v_{A}^{2} = - 2 g (\frac{H}{2})$
$\Rightarrow 0 - 400 = - 2 \times 10 \times \frac{H}{2}$
$\Rightarrow 40 m = H$

Q. A ball is projected vertically upwards. Its speed at half of maximum height is 20m/s. The maximum height attained by it is [Take g=10ms2]