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  4. A ball is projected vertically upwards. Its speed at half of maximum height is 20 m / s. The maximum height attained by it is [Take .g=10 ms 2]

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Q. A ball is projected vertically upwards. Its speed at half of maximum height is $20\, m / s$. The maximum height attained by it is [Take $\left.g=10\, ms ^{2}\right]$

Motion in a Straight Line

Solution:

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$v_{B}^{2}-v_{A}^{2}=-2 g\left(\frac{H}{2}\right)$
$\Rightarrow 0-400=-2 \times 10 \times \frac{H}{2}$
$\Rightarrow 40\, m = H$