A 64watt bulb emit monochromatic radiations of 310nm , emitted radiation strike on a metal surface of work function 4.7eV . then the number of photoelectrons emitted per second will be -

Question

A 64watt bulb emit monochromatic radiations of 310nm , emitted radiation strike on a metal surface of work function 4.7eV . then the number of photoelectrons emitted per second will be - (A) 0 (B) 1020 (C) 16× 1019 (D) 4× 1019

Tardigrade Admin · Accepted Answer

Here, W>(Ephoton) incident ∴ No photoelectron will be emitted.

Q. A $64 w a tt$ bulb emit monochromatic radiations of $310 nm$ , emitted radiation strike on a metal surface of work function $4.7 e V$ . then the number of photoelectrons emitted per second will be -

$0$

$1 0^{20}$

$16 \times 1 0^{19}$

$4 \times 1 0^{19}$

Here, $W > (E_{p h o t o n})$ incident
$∴$ No photoelectron will be emitted.

Q. A 64watt bulb emit monochromatic radiations of 310nm , emitted radiation strike on a metal surface of work function 4.7eV . then the number of photoelectrons emitted per second will be -

0

1020

16×1019

4×1019

Here, W>(Ephoton​) incident ∴ No photoelectron will be emitted.

Q. A $64 w a tt$ bulb emit monochromatic radiations of $310 nm$ , emitted radiation strike on a metal surface of work function $4.7 e V$ . then the number of photoelectrons emitted per second will be -

$0$

$1 0^{20}$

$16 \times 1 0^{19}$

$4 \times 1 0^{19}$

Here, $W > (E_{p h o t o n})$ incident
$∴$ No photoelectron will be emitted.