Question

A $64watt$ bulb emit monochromatic radiations of $310nm$ , emitted radiation strike on a metal surface of work function $4.7eV$ . then the number of photoelectrons emitted per second will be -

• A. $0$
• B. $10^{20}$
• C. $16\times 10^{19}$
• D. $4\times 10^{19}$

Answer 1

Answer: (A)

Here, $W>\left(E_{photon}\right)$ incident
$\therefore $ No photoelectron will be emitted.