Question

A $60\mu F$ capacitor is connected to a $110V,60HzAC$ supply. The rms value of the current in the circuit is

• A. 2 A
• B. 2.49 A
• C. 1.85 A
• D. 2.05 A

Answer 1

Answer: (B)

$X_C=\frac{1}{2\pi vC}=\frac{1}{2(3.14)\left(60s^{-1}\right)\left(60\times 10^{-6}F\right)}$
$=44.2\Omega$
$I_{\text{ rms}}=\frac{{\epsilon }_{\text{rms}}}{X_C}=\frac{110V}{44.2\Omega }$
$=2.49A$