A 5 mL solution of H2O2 liberates 0.508 g of Iodine from an acidified KI solution. What is the volume strength of the H2O2 solution?

Question

A 5 mL solution of H2O2 liberates 0.508 g of Iodine from an acidified KI solution. What is the volume strength of the H2O2 solution? (A) 2.2 % (B) 3.8 % (C) 4.48 % (D) None of these

Tardigrade Admin · Accepted Answer

Meq. of H2O2 = Meq. of I2 ⇒ (WH2O2/34) × 2 × 1000 = (0.508/254) × 2 × 1000 ∴ WH2O2 = 0.06 g H2O2 → H2O2 + (1/2) O2 ∵ 34 g H2O2 gives 11.2 litres of O2 at STP ∴ 0.068 g gives = (11.2/34)× 0.068 = 22.4 ml O2 ∴ Volume Strength of H2O2 = (22.4/5) = 4.48 volume

Q. A $5 m L$ solution of $H_{2} O_{2}$ liberates $0.508 g$ of Iodine from an acidified $K I$ solution. What is the volume strength of the $H_{2} O_{2}$ solution?

$2.2%$

$3.8%$

$4.48%$

None of these

Q. A 5mL solution of H2​O2​ liberates 0.508g of Iodine from an acidified KI solution. What is the volume strength of the H2​O2​ solution?

2.2%

3.8%

4.48%

None of these

Meq. of H2​O2​= Meq. of I2​ ⇒34WH2​O2​​​×2×1000 =2540.508​×2×1000 ∴WH2​O2​​=0.06g H2​O2​→H2​O2​+21​O2​ ∵34gH2​O2​ gives 11.2 litres of O2​ at STP ∴0.068g gives =3411.2​×0.068=22.4mlO2​ ∴ Volume Strength of H2​O2​ =522.4​=4.48 volume

Q. A $5 m L$ solution of $H_{2} O_{2}$ liberates $0.508 g$ of Iodine from an acidified $K I$ solution. What is the volume strength of the $H_{2} O_{2}$ solution?

$2.2%$

$3.8%$

$4.48%$