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  4. A 5 mL solution of H2O2 liberates 0.508 g of Iodine from an acidified KI solution. What is the volume strength of the H2O2 solution?

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Q. A $5\, mL$ solution of $H_2O_2$ liberates $0.508 \,g$ of Iodine from an acidified $KI$ solution. What is the volume strength of the $H_2O_2$ solution?

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Solution:

Meq. of $H_2O_2 =$ Meq. of $I_2$
$\Rightarrow \frac{W_{H_2O_2}}{34} \times 2 \times 1000$
$ = \frac{0.508}{254} \times 2 \times 1000$
$\therefore W_{H_2O_2} = 0.06\,g$
$H_2O_2 \to H_2O_2 + \frac{1}{2} O_2$
$\because 34\,g \,H_2O_2$ gives $11.2$ litres of $O_2$ at $STP$
$\therefore 0.068\,g$ gives $= \frac{11.2}{34}\times 0.068 = 22.4 \,ml\,O_2$
$\therefore $ Volume Strength of $H_2O_2$
$ = \frac{22.4}{5} = 4.48$ volume