A 5 C charge experience a force of 2000 N when moved between two points separated by a distance of 2 cm in a uniform electric field. The potential difference between the two points is

Question

A 5 C charge experience a force of 2000 N when moved between two points separated by a distance of 2 cm in a uniform electric field. The potential difference between the two points is (A) 8 V (B) 200 V (C) 800 V (D) 20000 V

Tardigrade Admin · Accepted Answer

E=(2000/5) N C -1=400 NC -1 Now, V=E r=400 × (2/100) V =8 V

Q. A $5 C$ charge experience a force of $2000 N$ when moved between two points separated by a distance of $2 c m$ in a uniform electric field. The potential difference between the two points is

8 V

200 V

800 V

20000 V

$E = \frac{2000}{5} N C^{- 1} = 400 N C^{- 1}$
Now, $V = E r = 400 \times \frac{2}{100} V$
$= 8 V$

Q. A 5C charge experience a force of 2000N when moved between two points separated by a distance of 2cm in a uniform electric field. The potential difference between the two points is

8 V

200 V

800 V

20000 V

E=52000​NC−1=400NC−1 Now, V=Er=400×1002​V =8V

Q. A $5 C$ charge experience a force of $2000 N$ when moved between two points separated by a distance of $2 c m$ in a uniform electric field. The potential difference between the two points is

$E = \frac{2000}{5} N C^{- 1} = 400 N C^{- 1}$
Now, $V = E r = 400 \times \frac{2}{100} V$
$= 8 V$