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  4. A 5 C charge experience a force of 2000 N when moved between two points separated by a distance of 2 cm in a uniform electric field. The potential difference between the two points is

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Q. A $5\, C$ charge experience a force of $2000\, N$ when moved between two points separated by a distance of $2\, cm$ in a uniform electric field. The potential difference between the two points is

Electrostatic Potential and Capacitance

Solution:

$E=\frac{2000}{5} N C ^{-1}=400\, NC ^{-1}$
Now, $V=E r=400 \times \frac{2}{100} V$
$ =8\, V$