A 4 μF capacitor is charged to 400 V and then its plates are joined through a resistance of 1 kΩ . The heat produced in the resistance is

Question

A 4 μF capacitor is charged to 400 V and then its plates are joined through a resistance of 1 kΩ . The heat produced in the resistance is (A) 0.16J (B) 1.28J (C) 0.64J (D) 0.32J

Tardigrade Admin · Accepted Answer

The energy stored in the capacitor =(1/2) textCV2=(1/2)× 4× text10- 6× text400× text400= text0.32 J This energy will be converted into heat in the resistor.

Q. A $4 μ F$ capacitor is charged to $400 V$ and then its plates are joined through a resistance of $1 k Ω$ . The heat produced in the resistance is

$0.16 J$

$1.28 J$

$0.64 J$

$0.32 J$

The energy stored in the capacitor
$= \frac{1}{2} CV^{2} = \frac{1}{2} \times 4 \times 10^{- 6} \times 400 \times 400 = 0.32 J$
This energy will be converted into heat in the resistor.

Q. A 4μF capacitor is charged to 400V and then its plates are joined through a resistance of 1kΩ . The heat produced in the resistance is

0.16J

1.28J

0.64J

0.32J