A 3cm long copper wire is stretched , to increase its length by 0.3 cm . find the lateral strain in the wire, if the Poisson's ratio for is 0.26.

Question

A 3cm long copper wire is stretched , to increase its length by 0.3 cm . find the lateral strain in the wire, if the Poisson's ratio for is 0.26. (A) 0.013 (B) 0.018 (C) 0.026 (D) 0.016

Tardigrade Admin · Accepted Answer

L = 3cm , Δ L = 0.3 cm , σ = 0.26 longitudinal strain (Δ L/L) = (0.3/3) = 0.1 σ = (later strain/Longitudinal strain) The Lateral Strain = σ × Longitudinal Strain = 0.26 × 0.1 = 0.026

Q. A 3cm long copper wire is stretched , to increase its length by 0.3 cm . find the lateral strain in the wire, if the Poisson's ratio for is 0.26.

0.013

0.018

0.026

0.016

L = 3cm , $Δ L = 0.3 c m, σ = 0.26$
longitudinal strain $\frac{Δ L}{L} = \frac{0.3}{3} = 0.1$
$σ = \frac{l a t er s t r ain}{L o n g i t u d ina l s t r ain}$
The Lateral Strain = $σ \times$ Longitudinal Strain = $0.26 \times 0.1 = 0.026$

Q. A 3cm long copper wire is stretched , to increase its length by 0.3 cm . find the lateral strain in the wire, if the Poisson's ratio for is 0.26.

0.013

0.018

0.026

0.016

L = 3cm , ΔL=0.3cm,σ=0.26 longitudinal strain LΔL​=30.3​=0.1 σ=Longitudinalstrainlaterstrain​ The Lateral Strain = σ× Longitudinal Strain = 0.26×0.1=0.026

L = 3cm , $Δ L = 0.3 c m, σ = 0.26$
longitudinal strain $\frac{Δ L}{L} = \frac{0.3}{3} = 0.1$
$σ = \frac{l a t er s t r ain}{L o n g i t u d ina l s t r ain}$
The Lateral Strain = $σ \times$ Longitudinal Strain = $0.26 \times 0.1 = 0.026$