A 3 m long rod has a mass of 0.98 kg . What is the moment of inertia about an axis passing through the centre and perpendicular to the length of the rod? (in . kg - m 2)

Question

A 3 m long rod has a mass of 0.98 kg . What is the moment of inertia about an axis passing through the centre and perpendicular to the length of the rod? (in . kg - m 2) (A) 1.03 (B) 0.73 (C) 0.53 (D) 0.40

Tardigrade Admin · Accepted Answer

Moment of inertia about an axis passing through the centre and perpendicular to the length of rod I=(M L2/12) =(0.98 × 9/12) =(8.82/12) =0.73 kg m 2

Q. A $3 m$ long rod has a mass of $0.98 k g .$ What is the moment of inertia about an axis passing through the centre and perpendicular to the length of the rod? (in $k g - m^{2})$

$1.03$

$0.73$

$0.53$

$0.40$

Moment of inertia about an axis passing through the centre and perpendicular to the length of rod
$I = \frac{M L ^{2}}{12}$
$= \frac{0.98 \times 9}{12}$
$= \frac{8.82}{12}$
$= 0.73 k g m^{2}$

Q. A 3m long rod has a mass of 0.98kg. What is the moment of inertia about an axis passing through the centre and perpendicular to the length of the rod? (in kg−m2)

1.03

0.73

0.53

0.40