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Q. A $3 m$ long rod has a mass of $0.98 kg .$ What is the moment of inertia about an axis passing through the centre and perpendicular to the length of the rod? (in $\left. kg - m ^{2}\right)$

System of Particles and Rotational Motion

Solution:

Moment of inertia about an axis passing through the centre and perpendicular to the length of rod
$I=\frac{M L^{2}}{12}$
$=\frac{0.98 \times 9}{12}$
$=\frac{8.82}{12}$
$=0.73 \,kg\, m ^{2}$