A 2 ohm and a (.2/3.) ohm resistor are connected in parallel across a 3 volt battery. Then energy given out per minute is :-

Question

A 2 ohm and a (.2/3.) ohm resistor are connected in parallel across a 3 volt battery. Then energy given out per minute is :- (A) 540J (B) 1620J (C) 2160J (D) 1080J

Tardigrade Admin · Accepted Answer

Net resistance is R=(2 × 2 / 3/2 + 2 / 3)=0.5Ω The energy given out per minute is E=(V2/R)t=(32/0 . 5)× 60=1080J

Q. A $2$ ohm and a $(2/3)$ ohm resistor are connected in parallel across a $3$ volt battery. Then energy given out per minute is :-

$540 J$

$1620 J$

$2160 J$

$1080 J$

Net resistance is $R = \frac{2 \times 2/3}{2 + 2/3} = 0.5Ω$
The energy given out per minute is
$E = \frac{V ^{2}}{R} t = \frac{3 ^{2}}{0.5} \times 60 = 1080 J$

Q. A 2 ohm and a (2/3) ohm resistor are connected in parallel across a 3 volt battery. Then energy given out per minute is :-

540J

1620J

2160J

1080J