A 2 L flask contains 1.4 g nitrogen and 1.0 g hydrogen. The ratio of active mass of nitrogen and hydrogen would be

Question

A 2 L flask contains 1.4 g nitrogen and 1.0 g hydrogen. The ratio of active mass of nitrogen and hydrogen would be (A) 1: 3 (B) 1: 5 (C) 1.4: 1 (D) 1: 10

Tardigrade Admin · Accepted Answer

[ N 2]=(1.4/28 × 2), [ H 2]=(1/2 × 2) [ N 2]:[ H 2]=(1/40): (1/4)=1: 10

Q. A $2 L$ flask contains $1.4 g$ nitrogen and $1.0 g$ hydrogen. The ratio of active mass of nitrogen and hydrogen would be

$1 : 3$

$1 : 5$

$1.4 : 1$

$1 : 10$

$[N_{2}] = \frac{1.4}{28 \times 2}, [H_{2}] = \frac{1}{2 \times 2}$
$[N_{2}] : [H_{2}] = \frac{1}{40} : \frac{1}{4} = 1 : 10$

Q. A 2L flask contains 1.4g nitrogen and 1.0g hydrogen. The ratio of active mass of nitrogen and hydrogen would be

1:3

1:5

1.4:1

1:10