1. Tardigrade
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  3. Chemistry
  4. A 2 L flask contains 1.4 g nitrogen and 1.0 g hydrogen. The ratio of active mass of nitrogen and hydrogen would be

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Q. A $2\, L$ flask contains $1.4\, g$ nitrogen and $1.0 \,g$ hydrogen. The ratio of active mass of nitrogen and hydrogen would be

Equilibrium

Solution:

${\left[ N _{2}\right]=\frac{1.4}{28 \times 2}, \,\,\,\,\left[ H _{2}\right]=\frac{1}{2 \times 2} }$
${\left[ N _{2}\right]:\left[ H _{2}\right]=\frac{1}{40}: \frac{1}{4}=1: 10 }$