A 2 kW motor is used to pump water from a well 20 m deep. The quantity of water pumped out per second is nearly [Take, g=10 m / s 2 ]

Question

A 2 kW motor is used to pump water from a well 20 m deep. The quantity of water pumped out per second is nearly [Take, g=10 m / s 2 ] (A) 10 kg (B) 20 kg (C) 5 kg (D) 25 kg

Tardigrade Admin · Accepted Answer

Given, P=2 kW =2 × 103 W h=20 m ∴ P=(W/t) P=(m g h/t) ⇒ m=(P t/g h)=(2 × 103 × 1/10 × 20)=10 kg

Q. A $2 kW$ motor is used to pump water from a well $20 m$ deep. The quantity of water pumped out per second is nearly
[Take, $g = 10 m / s^{2}$ ]

$10 k g$

$20 k g$

$5 k g$

$25 k g$

Given, $P = 2 kW = 2 \times 1 0^{3} W$
$h = 20 m$
$∴ P = \frac{W}{t}$
$P = \frac{m g h}{t}$
$\Rightarrow m = \frac{Pt}{g h} = \frac{2 \times 1 0 ^{3} \times 1}{10 \times 20} = 10 k g$

Q. A 2kW motor is used to pump water from a well 20m deep. The quantity of water pumped out per second is nearly [Take, g=10m/s2 ]

10kg

20kg

5kg

25kg