Question

A $2 \,kW$ motor is used to pump water from a well $20 \, m$ deep. The quantity of water pumped out per second is nearly
[Take, $g=10 \,m / s ^2$ ]

• A. $10 \,kg$
• B. $20 \, kg$
• C. $5 \,kg$
• D. $25 \, kg$

Answer 1

Answer: (A)

Given, $P=2\, kW =2 \times 10^3 W$
$ h=20 \,m $
$ \therefore P=\frac{W}{t} $
$P=\frac{m g h}{t} $
$ \Rightarrow m=\frac{P t}{g h}=\frac{2 \times 10^3 \times 1}{10 \times 20}=10\, kg$