A +2 B +3 C leftharpoons AB 2 C 3 Reaction of 6 g of A , 6 × 1023 atoms of B 0.036 mole of C yields 4.8 g of compound AB 2 C 3. If the atomic masses of A C are 60 80 amu respectively, the atomic mass of B is:

Question

A +2 B +3 C leftharpoons AB 2 C 3 Reaction of 6 g of A , 6 × 1023 atoms of B 0.036 mole of C yields 4.8 g of compound AB 2 C 3. If the atomic masses of A C are 60 80 amu respectively, the atomic mass of B is: (A) 60 amu (B) 50 amu (C) 90 amu (D) 120 amu

Tardigrade Admin · Accepted Answer

no. of moles of A =0.1 no. of moles of B =1 no of moles of C =0.036 C is limiting reagent as it is present in least amount AB 2 C 3 formed =(0.036/3)=0.012 so, molar mass of AB 2 C 3=(4.8/0.012)=400 ⇒ 60+2 x+80 × 3=400 x=50

Q. A+2B+3C⇌AB2​C3​ Reaction of 6g of A,6×1023 atoms of B & 0.036 mole of C yields 4.8g of compound AB2​C3​. If the atomic masses of A & C are 60 & 80 amu respectively, the atomic mass of B is:

60 amu

50 amu

90 amu

120 amu

no. of moles of A=0.1 no. of moles of B=1 no of moles of C=0.036 C is limiting reagent as it is present in least amount AB2​C3​ formed =30.036​=0.012 so, molar mass of AB2​C3​=0.0124.8​=400 ⇒60+2x+80×3=400 x=50

Q. $A + 2 B + 3 C ⇌ A B_{2} C_{3}$
Reaction of $6 g$ of $A, 6 \times 1 0^{23}$ atoms of $B$ & $0.036$ mole of C yields $4.8 g$ of compound $A B_{2} C_{3}$ . If the atomic masses of $A$ & $C$ are $60$ & $80$ amu respectively, the atomic mass of $B$ is: