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  4. A +2 B +3 C leftharpoons AB 2 C 3 Reaction of 6 g of A , 6 × 1023 atoms of B 0.036 mole of C yields 4.8 g of compound AB 2 C 3. If the atomic masses of A C are 60 80 amu respectively, the atomic mass of B is:

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Q. $A +2 B +3 C \rightleftharpoons AB _{2} C _{3}$
Reaction of $6 \,g$ of $A , 6 \times 10^{23}$ atoms of $B$ & $0.036$ mole of C yields $4.8 \,g$ of compound $AB _{2} C _{3}$. If the atomic masses of $A$ & $C$ are $60$ & $80$ amu respectively, the atomic mass of $B$ is:

Some Basic Concepts of Chemistry

Solution:

no. of moles of $A =0.1$

no. of moles of $B =1$

no of moles of $C =0.036$

$C$ is limiting reagent as it is present in least amount

$AB _{2} C _{3}$ formed $=\frac{0.036}{3}=0.012$

so, molar mass of $AB _{2} C _{3}=\frac{4.8}{0.012}=400$

$\Rightarrow 60+2 x+80 \times 3=400$

$x=50$