A 140 g ball, in horizontal flight with a speed upsilon1 of 39.0 m/s, is struck by a bat. After leaving the bat, the ball travels in the opposite direction with speed upsilon2=39.0 m/s . If the impact time Δ t for the ball-bat collision is 1.20 ms, what average net force acts on the ball?

Question

A 140 g ball, in horizontal flight with a speed upsilon1 of 39.0 m/s, is struck by a bat. After leaving the bat, the ball travels in the opposite direction with speed upsilon2=39.0 m/s . If the impact time Δ t for the ball-bat collision is 1.20 ms, what average net force acts on the ball? (A) 1308 N (B) 1090 N (C) 9100 N (D) 980 N

Tardigrade Admin · Accepted Answer

F=((m(v1-v2)./t) =(140 × 10-3(39+39)/12 × 10-3) =(1400 × 78/12)=9100 N

Q. A 140g ball, in horizontal flight with a speed υ1​ of 39.0m/s, is struck by a bat. After leaving the bat, the ball travels in the opposite direction with speed υ2​=39.0m/s . If the impact time Δt for the ball-bat collision is 1.20ms, what average net force acts on the ball?

1308 N

1090 N

9100 N

980 N

F=t(m(v1​−v2​)​ =12×10−3140×10−3(39+39)​ =121400×78​=9100N

$F = \frac{( m ( v _{1} - v _{2} )}{t}$
$= \frac{140 \times 1 0 ^{- 3} ( 39 + 39 )}{12 \times 1 0 ^{- 3}}$
$= \frac{1400 \times 78}{12} = 9100 N$