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Q. A $140 \,g$ ball, in horizontal flight with a speed $ \upsilon_{1} $ of $39.0 \,m/s$, is struck by a bat. After leaving the bat, the ball travels in the opposite direction with speed $ \upsilon_{2}=39.0\,m/s $ . If the impact time $ \Delta t $ for the ball-bat collision is $1.20\, ms$, what average net force acts on the ball?

AMUAMU 2013

Solution:

$F=\frac{\left(m\left(v_{1}-v_{2}\right)\right.}{t}$
$=\frac{140 \times 10^{-3}(39+39)}{12 \times 10^{-3}}$
$=\frac{1400 \times 78}{12}=9100 \,N$