Question

A $1250W$ heater operates at $115V$. What is the resistance of the heating coil?

• A. $1.6\Omega$
• B. $13.5\Omega$
• C. $1250\Omega$
• D. $10.6\Omega$

Answer 1

Answer: (D)

Given, $V=115V$
and $P=1250W$
We know,
$R=\frac{V^2}{P}$
So, $R=\frac{(115{)}^2}{1250}$
$=10.58\Omega$
$R=10.6\Omega$