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Q. A $1250\, W$ heater operates at $115\, V$. What is the resistance of the heating coil?

Delhi UMET/DPMTDelhi UMET/DPMT 2011Electromagnetic Induction

Solution:

Given, $V=115\, V$
and $P=1250\, W$
We know,
$R=\frac{V^{2}}{P}$
So, $R=\frac{(115)^{2}}{1250}$
$=10.58\, \Omega$
$R= 10.6\, \Omega$