A 110 watt, 110 volt lamp is connected in series with an electrolytic cell containing CdSO4 . What mass of cadmium will be deposited by the current flowing for 10 hour? (Atomic mass of Cd = 112.4)

Question

A 110 watt, 110 volt lamp is connected in series with an electrolytic cell containing CdSO4 . What mass of cadmium will be deposited by the current flowing for 10 hour? (Atomic mass of Cd = 112.4) (A) 20.96 g (B) 91 g (C) 17 g (D) 26 g

Tardigrade Admin · Accepted Answer

P = VI I=(P/V)=(110/110)=1 Equivalent mass of Cd =(A t o m i c m a s s/V a l e n c y) =(112.4/2)=56.2 W=(I t E/96500)=(1 × (. 10 × 60 × 60 .) × 56.2/96500) = 20.96 g.

Q. A 110 watt, 110 volt lamp is connected in series with an electrolytic cell containing $C d S O_{4}$ . What mass of cadmium will be deposited by the current flowing for 10 hour? (Atomic mass of Cd = 112.4)

20.96 g

91 g

17 g

26 g

P = VI

$I = \frac{P}{V} = \frac{110}{110} = 1$

Equivalent mass of Cd $= \frac{A t o mi c ma ss}{Va l e n cy}$

$= \frac{112.4}{2} = 56.2$

$W = \frac{I tE}{96500} = \frac{1 \times ( 10 \times 60 \times 60 ) \times 56.2}{96500}$

$= 20.96 g .$

Q. A 110 watt, 110 volt lamp is connected in series with an electrolytic cell containing CdSO4​ . What mass of cadmium will be deposited by the current flowing for 10 hour? (Atomic mass of Cd = 112.4)