A 100 Ω electric iron is connected to 200 V , 50 Hz ac source. Calculate average power delivered to iron, peak power and energy spent in one minute?

Question

A 100 Ω electric iron is connected to 200 V , 50 Hz ac source. Calculate average power delivered to iron, peak power and energy spent in one minute? (A) 400 W , 800 W , 12 × 105 J (B) 400 W , 900 W , 1.2 × 105 J (C) 500 W , 800 W , 6 × 105 J (D) 400 W , 900 W , 60 × 105 J

Tardigrade Admin · Accepted Answer

Here, R =100 Ω, E v =200 V , n =50 Hz As power/cycle =EvIv=Ev × (Ev/R) =((200)2/100) =400 watt peak power / cycle =E0I0= √2 E v × √2 I v =2 EvIv = 2 × 400 = 800 W As the frequency is 50 Hz ∴ Average power spent in one second = 400 × 50 ∴ Energy spent in one minute =400 × 50 × 60 =12 × 105 J

Q. A $100Ω$ electric iron is connected to $200 V, 50 Hz$ ac source. Calculate average power delivered to iron, peak power and energy spent in one minute?

$400 W, 800 W, 12 \times 1 0^{5} J$

$400 W, 900 W, 1.2 \times 1 0^{5} J$

$500 W, 800 W, 6 \times 1 0^{5} J$

$400 W, 900 W, 60 \times 1 0^{5} J$

Q. A 100Ω electric iron is connected to 200V,50Hz ac source. Calculate average power delivered to iron, peak power and energy spent in one minute?

400W,800W,12×105J

400W,900W,1.2×105J

500W,800W,6×105J

400W,900W,60×105J

Q. A $100Ω$ electric iron is connected to $200 V, 50 Hz$ ac source. Calculate average power delivered to iron, peak power and energy spent in one minute?

$400 W, 800 W, 12 \times 1 0^{5} J$

$400 W, 900 W, 1.2 \times 1 0^{5} J$

$500 W, 800 W, 6 \times 1 0^{5} J$

$400 W, 900 W, 60 \times 1 0^{5} J$