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Q.
A $100 \Omega$ electric iron is connected to $200 V , 50 Hz$ ac source. Calculate average power delivered to iron, peak power and energy spent in one minute?
Alternating Current
Solution:
Here, $R =100 \Omega, E _{ v }=200 V , n =50 Hz$
As power/cycle $=E_{v}I_{v}=E_{v} \times \frac{E_{v}}{R}$
$=\frac{(200)^{2}}{100} =400$ watt
peak power / cycle $=E_{0}I_{0}= \sqrt{2} E _{ v } \times \sqrt{2} I _{ v }$
$=2\, E_{v}I_{v} = 2 \times 400 = 800\,W$
As the frequency is $50\, Hz$
$\therefore $ Average power spent in one second $= 400 \times 50 $
$\therefore $ Energy spent in one minute $=400 \times 50 \times 60 =12 \times 10^{5}\, J$