A 10 m long iron chain of linear mass density 0.8 kg m -1 is hanging freely from a rigid support. If g =10 ms -2, then the power required to left the chain upto the point of support in 10 second

Question

A 10 m long iron chain of linear mass density 0.8 kg m -1 is hanging freely from a rigid support. If g =10 ms -2, then the power required to left the chain upto the point of support in 10 second (A) 10 W (B) 20 W (C) 30 W (D) 40 W

Tardigrade Admin · Accepted Answer

m =10 × 0.8 kg =8 kg height of iron chain =5 m P =( mgh / t )=(8 × 10 × 5/10) W =40 W

Q. A $10 m$ long iron chain of linear mass density $0.8 k g m^{- 1}$ is hanging freely from a rigid support. If $g = 10 m s^{- 2}$ , then the power required to left the chain upto the point of support in $10$ second

10 W

20 W

30 W

40 W

$m = 10 \times 0.8 k g = 8 k g$
height of iron chain $= 5 m$
$P = \frac{m g h}{t} = \frac{8 \times 10 \times 5}{10} W = 40 W$

Q. A 10m long iron chain of linear mass density 0.8kgm−1 is hanging freely from a rigid support. If g=10ms−2, then the power required to left the chain upto the point of support in 10 second